calculate percentage composition of carbon and urea where c=12 o=16 n=14 h=1
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Question is little wrong. We have to find the % composition of the Carbon in the urea.
Now, Molar mass of the Urea = 60 g/mole.
Mass of the Carbon is 1 mole of the Urea(NH₂CONH₂) = 12 g.
∴ % Composition of C in urea = 12/60 × 100%
= 100/5
= 20%
Hence, In 1 mole of the Urea, 20% of the Carbon is present.
Hope it helps.
Now, Molar mass of the Urea = 60 g/mole.
Mass of the Carbon is 1 mole of the Urea(NH₂CONH₂) = 12 g.
∴ % Composition of C in urea = 12/60 × 100%
= 100/5
= 20%
Hence, In 1 mole of the Urea, 20% of the Carbon is present.
Hope it helps.
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