Question

calculate percentage concentration of nitrogen in (nh4)2co3

Answer 1

molecular wt.= 14*2+1*8+6+16*3=90
90 g of N contain 28 g
100 g of (nh4)2co3 contain=
$\frac{28}{90} \times 100 = 31.11$
90 g of H contain 8 g
100 g of (nh4) 2co3 contain=
$\frac{8}{90} \times 100 = 8.88$
90 g of C contain 6 g
100 g of (nh4) 2co3 contain=
$\frac{6}{90} \times 100 = 6.66$
90 g of O contain 48 g
100 g of (nh4) 2co3 contain=
$\frac{48}{90} \times 100 = 53.33$
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Hope this help you...