Question

Calculate percentage of C,H & O present in methanol​

Answer 1

Answer:

We have, molar mass of CH3OH = 12 + 4×1 + 16 = 32. Mass percentage of carbon = 12/32 × 100 = 0.375 × 100 = 37.5 %. Mass percentage of Hydrogen = 4/32 × 100 = 12.5 %

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Answer 2

Answer:

We have, molar mass of CH3OH = 12 + 4×1 + 16 = 32. Mass percentage of carbon = 12/32 × 100 = 0.375 × 100 = 37.5 %. Mass percentage of Hydrogen = 4/32 × 100 = 12.5 %.