Chemistry, asked by esowmikareddynchrmc1, 14 days ago

Calculate percentage of Mg+) and Mg2+
(IE), and (IE), of Mg(g)are 740, 1540 kJ mol
mole of Mg(g) absorbs 1300 kJ of energy.
(9) if 1
(A) %Mg+ = 50% %Mg+2 = 50%
(B) % Mg+ = 68.35% %Mg+2 = 31.65%
(C) % Mg+ = 62% %Mg+2 = 38%
(D) % Mg+ = 60%
%Mg+2 = 40%​

Answers

Answered by jyotikarathore2007
0

Answer:

% Mg+ = 68.35% %Mg+2 = 31.65%

Explanation:

pls Mark me as a brainlist

Similar questions