Question

Calculate percentage of so42 - and h2o in pure crystals of mohr salt feso4.(nh4)2so4.6h2o

Answer 1

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Answer 2

Answer:

The percentage of SO₄⁻² present in mohr salt is 48.98%.

The percentage of H₂O present in mohr salt is 27.55%.

Explanation:

Given,

The mohr salt FeSO₄.(NH₄)₂SO₄.6H₂O

To find,

The percentage of SO₄⁻² and H₂O present in mohr salt.

Calculation,

We can calculate the molar mass of mohr salt(M) as:

M = 56 + 32 + 64 + 28 +8 + 32 + 64 + 108.

⇒ M = 392

Now the molar mass of SO₄⁻² (m1) = 96

And the molar mass of H₂O (m2) = 18

Percentage of  SO₄⁻²:

As the mohr salt is having 2 SO₄⁻² ions so, the total mass of SO₄⁻² in the formula is 192.

Therefore, the percentage of SO₄⁻² present in mohr salt is:

$\frac{192}{392} \times 100$

= 48.98%

Percentage of H₂O:

As the mohr salt is having 6 H₂O so the total mass of H₂O molecules is 108.

Therefore, the percentage of H₂O present in mohr salt is:

$\frac{108}{392} \times 100$

= 27.55%

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