Question

calculate percentage of various elements in Na2Co3.[Na=23,C=12,O=16]​

Answer 1

Answer:

In Na2CO3 :

Sodium = 43.4 %

Carbon = 11.3% and

Oxygen = 45.3%

Explanation:

Relative molecular mass of Na2CO3

                        = 23x2 + 12 + 16x3

                        = 46 + 12 + 48 =106 amu

Since 106g of Na2CO3 contains 46g of sodium,

∴ 100g of Na2CO3 contains 46*100/106 of sodium

                       = 4600/106 = 43.4 g of sodium

Similarly, 106 g Na2CO3 contains 12g of carbon.

∴ 100g of Na2Co3 contains 12*100/106

                          =1200/106 = 11.3 g of Carbon

Again, 106 g of Na2CO3 contains 48g of Oxygen.

∴ 100 g of Na2CO3 contains 48*100/106

            = 4800/106 = 45.3 g of Oxygen .

                                      Hope it helps ..........