Question

calculate ph 4*10^_8M HNO3​

Answer 1

Answer:

HNO3 is a strong acid

HNO3 = H+ + NO3-

we can NOT neglet the autoionization of water :

H2O <=> H+ + OH- for which Kw = 1.0 x 10^-14

because [H+][OH-]= 1.0 x 10^-14

[H+]= 1.0 x 10^-7 M

total concentration of H+ = 1.0 x 10^-7 + 4.8 x 10^-8=1.5 x 10^.7 M

pH = 6.8

PLZ FOLLOW ME

Explanation:

Answer 2

Answer:

HNO3 is a strong acid

HNO3 = H+ + NO3-

we can NOT neglet the autoionization of water :

H2O <=> H+ + OH- for which Kw = 1.0 x 10^-14

because [H+][OH-]= 1.0 x 10^-14

[H+]= 1.0 x 10^-7 M

total concentration of H+ = 1.0 x 10^-7 + 4.8 x 10^-8=1.5 x 10^.7 M

pH = 6.8

PLZ FOLLOW ME

Explanation: