calculate PH and p o h of 10^-8 M HCL solution
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Explanation:
[H+] = 10‐⁸ M
As we can see,
The concentration of H+ is very low.
Hence, It is a very dilute solution.
So, we have to consider Concentration of H+ from H2O also.
[H+] of water = 10‐⁷ M
Total [H+] = (10‐⁸ + 10‐⁷ ) M ~ 10‐⁷ (approx.)
pH = -log[H+] = 7 (approx.)
pOH = 14 - pH = 14 - 7 = 7 (approx.)
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