Question

Calculate pH and poH for 0.02M HCl (log 2=0.3010)​

Answer 1

Answer:

HCl + H2O 》 H30+ + Cl-

0.02 M HCl will produce 0.02 M H30+ ions

pH = — log [ H30+]

pH = — log 2 × 10^-2

pH = 1.699

pOH = 14 — pH = 14 — 1.699 = 12.301