Question

calculate ph and poh of 0.003 m hcl solution ​

Answer 1

Explanation:

(i) 0.003MHCl:

H2O + HCl ↔ H3O+ + Cl- Since HCl is completely ionized, [H3O+] = [ HCl] ...

Hence, the pH of the solution is 2.52. (b) 0.005 M NaOH.

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Answer 2

Answer:

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