Question

Calculate pH and pOH of 0.05M ca(OH)2 solution

Answer 1

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Explanation:

Ca(OH)2-------- Ca^2+. +. 2OH ^-

1 mole of Ca(OH)2 gives 2 mole of OH.

0.05 mole of Ca(OH)2 gives 0.1 mole of OH

pOH = - log [OH]

pOH = -log[0.1]

pOH = 1

pH+pOH = 14

pH = 14 - 1

pH = 13