Question

Calculate pH [H+] , [oH-] of a 3.2×10-3 M
solution of Ba(oH]2 in water at 25°c

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Answer 1

Answer:

[oH-] of a 3.2×10-3 M

pOH = - log(3.2*10^-3)

pOH = 2.495

pH = 14 - 2.495 = 11.505