Question

calculate pH of 0.01 mol/L NAOH SOLUTIONS​

Answer 1

Answer:

pH = 12

Explanation:

NaOH ----> (Na+) + (OH-)

0.01................0.01.........0.01

[H+] × [OH-] = 10^(-14)

[H+] × 10^(-2) = 10^(-14)

[H+] = 10^(-12)

=> pH = -log[H+]

=> pH = -log {10^(-12)}

=> pH = - [ -12× log10 ]

=> pH = 12