Question

calculate ph of 0.05m naoh

Answer 1

since of is Na OH We have to find pOH
pOH = - log (0.05)
= - log (5× 10^-2)
= - log 5 + 2 log 10
= 2 - log 5 ( since log 10 =1)
= 2 - 0.6990
pOH = 1.301

pH + pOH =14
pH = 14 -1.301
pH = 12.69

Answer 2

For 0.1 m NaOH=>
pOH = -log[OH- ] = -log(0.1) = 1
pH + pOH = 14,
So pH = 13

For 0.05 m NaOH=>
pOH = -log(0.05) = 1.3
pH = 14 - 1.3
= 12.7 Ans.