Calculate pH of 0.1(M) acetic acid at 25°C temperature. Given ka of CH3COOH = 1.8×10^-18 (at 25°C).
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PH = Pka minus half log[conc]
Pka = log (ka)
log[c] = log 1 ÷ 10
log(c) = -1
Pka = -18 + 0.25 = -17.75
Ph = - 17.75 + 0.5 = -17.25.
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