Question

Calculate ph of 0.2 m aqueous solution of sodium butyrate

Answer 1

Answer:The pH of 0.2 m aqueous solution of sodium butyrate is 0.69.

Explanation:

$C_3H_6COOH+NaOH\rightarrow C_3H_6COO^-Na^+ +H_2O$

Since, 0.2 M of sodium butyrate is present in solution which means hydronium ions($[H^+]$) given by butyric acid will be same

$[C_3H_6COO^-Na^+]=[H^+_{\text{From butyric acid}}]=0.2M$

$pH=-log[H^+]=-log[0.2]=0.69$

The pH of 0.2 m aqueous solution of sodium butyrate is 0.69.

Answer 2

Hey buddy,

◆ Answer-
pH = 9

◆ Explaination-
# Given-
Ka = 2×10^-5
pKw = 14
C = 0.2 m

# Solution-
Sodium butyrate is a salt of weak acid and strong base.
C3H6COOH + NaOH ---> C3H6COONa + H20

pH of the solution is given by-
pH = 1/2 pKw + 1/2 pKa + 1/2 log(C)
pH = 14/2 + 1/2 log(2×10^-5) + 1/2 log(0.2)
pH = 7 + 2.3494 - 0.3495
pH = 9

Therefore, pH of sodium butyrate is 9.

Hope this helps you...