Calculate pH of 0.49 % weight by volume H2 S o4 solution.
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0.49% W/V means 0.49 g H2SO4 in 100ml solution
number of moles of H2SO4 = W/M = 0.49/98 = 0.005
so, 0.005 mole H2SO4 present in 100 ml water
now concentration of H+ ion is = 2 × molarity
because 1 h2so4 dissociate to give 2 H+ ions
therefore conc. H+ is,
=2× molarity
=2× (0.005×1000/100)
= 0.1
now, pH = - log (H+ )
= - log (10^-1)
= 1
therefore pH =1
number of moles of H2SO4 = W/M = 0.49/98 = 0.005
so, 0.005 mole H2SO4 present in 100 ml water
now concentration of H+ ion is = 2 × molarity
because 1 h2so4 dissociate to give 2 H+ ions
therefore conc. H+ is,
=2× molarity
=2× (0.005×1000/100)
= 0.1
now, pH = - log (H+ )
= - log (10^-1)
= 1
therefore pH =1
hrishikeshdeuri:
oh! yes I'm sorry
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