Question

calculate ph of 10^-2 M solition or Ba(LaC)2.ka for lactic acid is 10^-4​

Answer 1

Answer:

HEY MATE YOUR ANSWER

Explanation:

ANSWER

pKa of acetic acid=2×10−5 

pKa=−log[2×10−5]=5−log2=4.76

pH=0.5[pKa−logC]

pH=0.5[4.76−log10−3]

pH=3.88

Answer 2

Answer:

2.845

Explanation:

Step 1: The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7. In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

Step 2: We are aware that not every acid or base reacts with a chemical substance at the same pace. Other people respond extremely strongly, some people mildly, and some people don't react at all. We utilise a universal indicator that exhibits various colours at various concentrations of hydrogen ions in solution to objectively assess the strength of acids and bases. In most cases, the strength of acids and bases is quantified using their pH values.

Step 3: $\mathrm{pK}_{\mathrm{a}}$ of Barium hydroxide $=2 \times 10^{-4}$

$\mathrm{pK}_{\mathrm{a}}=-\log \left[2 \times 10^{-4}\right]$ $=-\log _{10}(2)+4$= 3.69

$\mathrm{pH}=0.5\left[\mathrm{pK}_{\mathrm{a}}-\log \mathrm{C}\right]$

$\mathrm{pH}=0.5\left[3.69-\log 10^{-2}\right]$

$\begin{aligned}& 0.5\left(3.69-\log _{10}\left(10^{-2}\right)\right) \\& \log _{10}\left(10^{-2}\right)=-2 \\& =0.5(3.69-(-2))\end{aligned}$

Simplify

=2.845

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