Question

Calculate Ph of 10-5M of naoh

Answer 1

n-factor of NaOH = 1

OH⁻ concentration = Normality of NaOH
                              = Molarity x n-factor
                              = 10⁻⁵ x 1
                              = 10⁻⁵  

Now, pOH = -㏒(OH⁻)

         pOH = -㏒(10⁻⁵)

         pOH = 5

We know pH + pOH = 14

                pH = 14 - 5 = 9


∴pH of 10⁻⁵M NaOH is 9

Answer 2

Answer:

hope the above will help a lot ✨✌