Question

calculate ph of 10M NH4OH which is 10 percent disociated​

Answer 1

Answer:

NH  

4

​  

OH→NH  

4

+

​  

+OH  

−

 

Conc. of [OH  

−

]=cα=  

C×K  

b

​  

 

​  

=  

0.001×10  

−5

 

​  

=10  

−4

 

So pOH=−log[OH  

−

]=4

pH=14−pOH=10

Explanation: