calculate ph of 10M NH4OH which is 10 percent disociated
Answers
Answered by
2
Answer:
NH
4
OH→NH
4
+
+OH
−
Conc. of [OH
−
]=cα=
C×K
b
=
0.001×10
−5
=10
−4
So pOH=−log[OH
−
]=4
pH=14−pOH=10
Explanation:
Similar questions