Question

Calculate pH of 10power -7M H2SO4​

Answer 1

Answer:

Ph = -log[H+]

then ph = -log(10 base)^10^-7 = -(-7)log(10 base) ^10

= 7

then ph = 7 (Neutral).

Hope it helps.....

Answer 2

The pH of $10^{-7}MH_{2}SO_{4}$ is 6.69.

Step-by-step explanation:

Given: $10^{-7}MH_{2}SO_{4}$

To find: the pH of this acid.

Formula to be used:  $pH=-log[H^{+}]$

Step 1 of 2

The pH can be calculated by using the formula $pH=-log[H^{+}]$.

The concentration of the $H^{+}$ ion in sulhpuric acid will also be $10^{-7}$, now substituting this in formula we will get:

$pH=-log[H^{+}]\\\\pH=-log[10^{-7}]\\\\pH=-(-7)log10\\\\pH=7*1\\\\pH=7$

The pH of acid cannot be 7. It means that it is highly diluted.

Step 2 of 2

Taking in consideration that water is also donating its $10^{-7}$ concentration.

So, the total concentration will be $10^{-7}+10^{-7}=2*10^{-7}$

Now calculating the pH:

$pH=-log[H^{+}]\\\\pH=-log[2*10^{-7}]\\\\pH=-log2+2log10\\\\pH=-0.301+7\\\\pH=6.69$