calculate pH of 5.0×10-4 M HNO3 (log 5.0=0.699)
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nitric acid is monobasic acid
so Molarity=Normality=[H]+
PH=_log[H]+
_log5×10_4
4_log5
4_0.699
=3.3
so Molarity=Normality=[H]+
PH=_log[H]+
_log5×10_4
4_log5
4_0.699
=3.3
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