Calculate pH of a 1.0×10 power -8 M solution of HCl.
Sriyathmika:
answer is wrong....
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Given,
Concentration of HCl = 1.0 × 10⁻⁸
As HCl is a strong acid, it dissociates as,
HCl → H⁺ + Cl⁻
1.0 × 10⁻⁸ 1.0 × 10⁻⁸ 1.0 × 10⁻⁸
Formula of pH is-
pH = -log[H⁺]
Thus,
pH of HCl solution = -log[1.0 × 10⁻⁸]
= -(-8)
= 8
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