Question

calculate pH of a 1.0 into 10 raise to power minus 8 M solution of HCl​

Answer 1

Answer:

H+] total =[H+] acid +[H+] water

Since, HCl is a strong acid and is completely ionized

[H+]HCl=1.0×10−8

The concentration of H+ from ionization is equal to the [OH–] from water,

[H+]H2O=[OH–]H2O

=x (say)

[H+]total=1.0×10−8+x

But

[H+][OH–]=1.0×10−14

(1.0×10−8+x)(x)=1.0×10−14

X2+10−8x–10−14=0

Solving for x, we get x=9.5×10−8

Therefore,

[H+]=1.0×10−8+9.5×10−8

=10.5×10−8

=1.05×10−7

pH=–log[H+]=