Question

Calculate pH of mixture containing 50 ml 0.05
(K for CH.00 = 1.8 10 K, for NA. = 18
)
10-5
and 50 ml 005 M CHCO​

Answer 1

Answer: pH of the mixture is 8.71

Explanation: Reaction is given as:

Reaction of NaOH and combine in 1:1 ratio to produce

Number of moles can be calculate by

Molarity of NaOH = 0.1M

Volume of NaOH = 50mL = 0.05L

Moles of NaOH = 0.005 moles

Total Volume of the mixture = 100mL = 0.1L

Concentration of will be

= 0.05moles/L

For salt hydrolysis of weak acid ( ) and strong base ( NaOH )

where, = 14

= 4.72 (given)

C = Concentration of that is 0.05moles/L

Putting the values in above equation, we get

pH = 8.71