calculate ph of solution obtained by mixing 100ml of 0.1M acetic acid and 100ml of 0.05M NaOH solution ka for acetic acid is 1.8*10^-6
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You will need to know the molarity of the NaOH. Let's assume the solution is 0.1M. NaOH is a strong base, so this will produce 0.1mol/L of OH ions in solution. This will produce a pH of 13.
You will need to take the negative log of 0.1 to find the pOH. This will work out to be 1.
Since pH + pOH = 14
We can calculate the pH to be 13.
This assumption we made about the base can only be used for strong bases which dissociate completely in water.
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Hope sriansh answer is correct
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