Question

calculate ph of solution obtained by mixing 1200 ml of 0.1M hno3 and 800 ml of 0.05M h2so4 and 2lit of water

Answer 1

Answer:

Moles of NaOH = 0.8*0.05=0.0040

Moles of HCl = 0.2*0.1=0.02

HCl + NaOH => NaCl + H2O

NaOH will get fully consumed and 0.02 - 0.004 = 0.016 moles of HCl will remain.

Concentration of HCl = Concentration of H+ ions = 0.016/(800 + 200)*1000 = 0.016M

pH = -log([H+]) = -log(0.016) = 1.8

Explanation:

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