Question

Calculate ph value of 0.002 M H2SO4

Answer 1

Answer:

pH= -log10 [H+] here molarity of H2SO4 given but [H+] means normality so {normality=molarity×valency(acidity),} then normality =0.002×2 , normality is 0.004N ,,,,,,,,pH=- log10 [0.004] , pH=-(-2.39), pH= 2.39