Question

calculate Poisson ratio for a mild steel specimen 30mm in diameter and 300mm long .when a 54 KN load is applied , extension of the bar 0.112 mm with a change in diameter of 0.00366 mm​

Answer 1

Explanation:

The equation for calculating Poisson's ratio is given as ν=(-ε_trans)/ε_axial. Transverse strain (ε_trans) is measured in the direction perpendicular to the applied force, and axial strain (ε_axial) is measured in the direction of the applied force.

Answer 2

Answer:

Explanation:

Given data:

Tensile load(F)=55KN

Diameter(d)=31mm

Gauge Length (L)=300mm

Extension (ΔL)=0.115mm

ΔdChange in diameter=0.00567 mm

i) Poisson's ratio μ= lateralstrain/longitudinalstrain

μ=0.00367310.115300

μ=0.308

2) Young's modulus=stressstrain

E=55∗103/π/4∗3120.115/300

E=190.09∗103N/mm2

3)E=3K(1−2μ)

190.09∗103=3K(1−2∗0.308)

Bulkmodulus(K)=165∗103N/mm2

4)E=2G(1+μ)

190.09∗103=2∗G(1+0.308)

Modulus of rigidity G=72.664∗103N/mm2