calculate power loss in electrical transmission cable,15 km long,carrying a current of 100 A 200kv.The resistance pr km of the cable is 0.2 ohm.
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Answers
Answer:
The power plant may generate power at 20kV, but if transmission was attempted without stepping this up then the plant could not possibly generate 100MVA with the line in the question. The total line resistance is 5 Ω , however for 100MVA at 20kV this would need to carry 5000A, at which current the line would drop 25kV - more than we started with.
In the general case the line power loss in MW/MVA (ignoring reactive losses) for a generated power of P MVA over a line resistance of RΩ using a transmission voltage of V kV is:
P2RV2
This is a percentage power loss of:
100PRV2
So for example if we stepped the line voltage up to 100 kV, then the line would lose 5MW/MVA (5%). At 200 kV this would drop to just 1.25 MW/MVA/%.
Notice a couple of consequences from these equations. Firstly the percentage loss is proportional to the power transmitted. So increasing the power over a given line reduces the profit margin. On the bright side however the percentage loss lowers in proportion to the square of the transmission voltage, or in other words doubling the voltage increases the power that we can transmit by four times for the same percentage loss.
Explanation:
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Answer:
total resistance = 15*0.2= 3 ohm
now, p= i^2R=10000*3= 30000w