Calculate power of an engine which can pull mass of 500 metric ton upon inclined plane
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An engine can pull a 500 metric ton load up an inclined plane rising 1m in 100m of horizontal distance with a speed of 10m per second. The frictional force offered by the plane is 2000 N. What is the power of the engine? Given g = 9.8 m/s².
Now let me answer it for you.
Lets convert the metric tons to Kgs.
1 tone = 1000 kg
Force = mass × acceleration due to gravity.
Mass = 500 × 1000 = 500000Kg
Force = 500000 × 9.8 = 4900000N
The resultant force = 4900000 - 2000 = 4898000N
Work done = Force × Distance (the height moved)
= 4898kN × 1 = 4898kJ
Power = work done/time
Time taken is :
100/10 = 10 seconds
Power = 4898kJ/10 = 489.8 kW
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