Calculate power of lamp
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Answer:
Total resistance in the circuit=24ohm
Total current across the circuit=0.25I
Potential difference across electric lamp=5V
Potential difference across conductor=1V
Explanation:
A)As conductor and bulb are connected in series
Total resistance R=R1+R2
Which is 20+4=24ohm
B)I=V/R
So I=6V/25 ohm=0.25A
C)0.25*resistance of lamp=0.25*20=5V
D)0.25*resistance of conductor=0.25*4=1V
HOPE IT HELPS
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