Physics, asked by wonderwomen3000, 10 months ago

calculate pressure due to water column of height 100m.(take g=10m s ^-2 and density of water =10^3kg m ^-3​

Answers

Answered by VishnuPriya2801
23

Answer:-

Given:

Acceleration due to gravity (g) = 10 m/s²

Density of water = 10³ kg/m³

Height = 100 m.

We know that,

Pressure = Force / Area.

  • Force = mass * acceleration
  • Area = Volume/height.

Force exerted = mass * 10

We know that,

Density = Mass/Volume

Hence,

→ 10³ = Mass / Volume

→ Mass = (10³) * (Volume)

→ Force exerted = 10³ * volume * 10

using a = a¹ and a ^ m * a^n = a^(m + n) we get,

→ Force exerted = 10^(3 + 1) * volume

→ Force = 10⁴ * Volume

And,

Area = Volume/height

  • Area = length * breadth
  • Volume = length * breadth * height
  • → Area = length * breadth * height/height

Hence,

Area occupied = Volume / 100

→ Pressure = (10⁴ * Volume)/(Volume/100)

→ Pressure = (10⁴ * Volume * 100) / Volume

(100 can be written as 10²)

→ Pressure = 10⁴ * 10²

→ Pressure = 10^(4 + 2)

→ Pressure = 10⁶ Pa

→ Pressure = 1 MPa

Therefore, the pressure exerted = 1 MPa.

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