calculate pressure exerted by 0.8 m vertical lenght of alchohol of density 0.80 gcm^-3 in SI unit. take g= 10 ms^-2
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Answer:
Vertical length of the alcohol column
(h)=0.8m
Density of alcohol (d)=0.8gcm
−3
=0.8×1000=800kgm
−3
[∴1gcm
−3
=1000kgm
−3
]
Pressure=hdg
=0.8×800×10
=6400Pa
Therefore, pressure exerted by the alcohol column is 6400 Pa.
Explanation:
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