Question

calculate pressure exerted by 0.8 m vertical lenght of alchohol of density 0.80 gcm^-3 in SI unit. take g= 10 ms^-2
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Answer 1

Answer:

Vertical length of the alcohol column

(h)=0.8m

Density of alcohol (d)=0.8gcm

−3

=0.8×1000=800kgm

−3

[∴1gcm

−3

=1000kgm

−3

]

Pressure=hdg

=0.8×800×10

=6400Pa

Therefore, pressure exerted by the alcohol column is 6400 Pa.

Explanation:

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