Question

Calculate pressure exerted by a screw on the wooden plank if area of contact of the screw is 0.5 mm2 and its weight is 50 n

Answer 1

Answer:

pressure = force/area

so,50/0.5=100n/mm^2

Answer 2

Given :

Area of contact of the screw (A) = 0.5 mm²

Weight = Force (F) = 50 N

To Find :

Pressure exerted by the screw on the wooden plank

Solution :

Force exerted by the screw (F) = weight = 50 N

Area of contact (A) = 0.5 mm²

                               = 0.5 × ($10^{-3}$)²

                               = 0.5 × $10^{-6}$ m²

Therefore,

Pressure exerted by the screw (P) = $\frac{Force (F)}{Area (A)}$

                                                          = $\frac{50}{0.5 * 10^-^6}$

                                                          = $10^8$  N/m²

Hence, The pressure exerted by the screw on the wooden plank is  $10^8$  N/m².