Question

calculate q and w for isothermal expansion of one mole of an ideal gas at 25°c from a volume of 40 to 56 dm^3 against a constant pressure 1 atm​

Answer 1

Answer:

Hello my friend

Explanation:

Since, the process is isothermal,

ΔU=ΔH=0

From the first law of thermodynamics

ΔU=q+w=0

q=−w

w=−2.303nRTlog

V

1

V

2

=−2.303×1×8.314×400log

10

20

=−2.303×1×8.314×0.3010=−2305.3J (Work done by system)

q=−w=2305.3J (Heat absorbed by the system)