Question

Calculate Q.D & CQD If Q1=64& Q3 67

Answer 1

Answer:

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$to \: find : \\ 1.Quartile \: Deviation \: (Q.D) \\ \\ 2. \: coefficient \: of \: quartile \: deviation \\ (C.Q.D) \\ \\ given : \\ lower \: quartile \: (Q.1) = 64 \\ \\ upper \: quartile \: (Q.3) = 67$

$we \: know \: that \\ \\ quartile \: deviation \: \: ie \: semi \: \\ inter \: quartile \: range \: is \: \\ \\ Q.D = \frac{Q.3 - Q.1}{2} \\ \\ = \frac{67 - 64}{2} \\ \\ = \frac{3}{2} \\ \\ Q.D= 1.5$

$similarly \\ we \: have \\ \\ C.Q.D = \frac{Q.3 - Q.1}{Q3 + Q.1} \\ \\ = \frac{67 - 64}{67 + 64} \\ \\ = \frac{3}{131} \\ \\ =0.0229007 \\ \\ C.Q.D ≈0.02$