Question

Calculate ratio of radius of 3rd bohr orbit of be3+ and 5th bohr orbit of li2+

Answer 1

R (RADIUS) DIRECTLY PROPORTIONAL TO N^2

3^2/4:5^2/3

9/4:25/3

27/100

27:100 ANSWER

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Answer 2

The correct answer is 27: 100.

Given: Orbits and elements.

To Find: Radius ratio of elements.

Solution:

Radius = $\frac{0.529*n^{2} }{Z}$     (where n is shell number and Z is atomic number)

The radius in proportional to $\frac{n^{2} }{z}$.

First element = $Be^{+3}$.

Orbit of first element = 3

Second element = $Li^{+2}$

Orbit of second element = 5

Radius ratio = $\frac{n_{1} ^{2} }{z_{1} } :\frac{n_{2} ^{2} }{z_{2} }$

= $\frac{3^{2} }{4 } :\frac{5^{2} }{3}$

= 27: 100

Hence, the radius ratio is 27: 100.

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