Question

calculate refractive index of the material whose angle of incidence is 90 degree and angle of refraction is 45 degree

Answer 1

Here

• sin i=90°
• sin r=45°

Using Snell' s law

$\boxed{\sf \mu=\dfrac{sin\: i}{sin\:r}}$

$\\ \sf\longmapsto \mu=\dfrac{90}{45}$

$\\ \sf\longmapsto \mu=2$

Answer 2

Answer:

The Refractive index of the medium is $\sqrt{2}$

Explanation:

Given that,for a material angle of incidence is 90* and the angle of refraction is 45*.We are required to find the refractive index of the material.

To find the refractive index of the material,we shall use snell"s law.It states that the refractive index of a material is the ratio of sine of angle of incidence to sine of angle of refraction.Hence,mathematically we write-

$\mu=\frac{sini}{sinr}$

Substituting the values of the given angles in the above relation,we get-

$\mu=\frac{sin90}{sin45}=\frac{1}{\frac{1}{\sqrt{2}}}=\sqrt{2}$

Therefore,the refractive index of the medium is found to be $\sqrt{2}$

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