Question

Calculate relationship between solubility product and solubility for BaF2​

Answer 1

Answer:

Ksp = 4s³. Here Ksp is solubility product and s is solubility.

Explanation:

BaF₂ ----------> Ba²⁺ + 2F⁻  (Equilibrium reaction).

Let solubility of BaF₂ be s.

Observe that for every mole of BaF₂ dissolved  one mole of Ba²⁺ and two moles of F⁻ ions are formed.

Since solubility of BaF₂ is s, [Ba²⁺] = s and [F⁻] = 2s.

We know that solubility product (Ksp) for BaF₂ is [Ba²⁺][F⁻]².

i.e Ksp = (s)(2s)²

∴ Ksp = 4s³.