Question

Calculate relative rate of effusion of so2 to ch4

Answer 1

for SO2;

                     M = 64

                     R1 = 1/8
                

               For CH4;

                    M = 16

                    R2= 4   

 

       SO,

            R1:R2=1 : 2

Answer 2

Answer: The ratio of effusion rates of sulfur dioxide and methane is 0.5

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of Sulfur dioxide = 64.066 g/mol

Molar mass of methane = 16.04 g/mol

By taking their ratio, we get:

$\frac{Rate_{SO_2}}{Rate_{CH_4}}=\sqrt{\frac{M_{CH_4}}{M_{SO_2}}}$

$\frac{Rate_{SO_2}}{Rate_{CH_4}}=\sqrt{\frac{16.04}{64.066}}\\\\\frac{Rate_{SO_2}}{Rate_{CH_4}}=0.5$

Hence, the ratio of rate of effusion of sulfur dioxide and methane will be 0.5