Calculate required heat energy (Q) to change 10g of water from 30 degrees Celsius to 40 degrees Celsius (special heat of water 1)
Answers
Explanation:
Mass of water = 10g
Mass of water = 10gInitial temperature = 30°C
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°C
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..Specific heat of substance is defined as the heat required to increase temperature of 1g substance by 1°C.
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..Specific heat of substance is defined as the heat required to increase temperature of 1g substance by 1°C.Specific heat of water = 1 cal/g °C
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..Specific heat of substance is defined as the heat required to increase temperature of 1g substance by 1°C.Specific heat of water = 1 cal/g °CFormula : Q = mcΔT
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..Specific heat of substance is defined as the heat required to increase temperature of 1g substance by 1°C.Specific heat of water = 1 cal/g °CFormula : Q = mcΔT☃ Let's calculate :D
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..Specific heat of substance is defined as the heat required to increase temperature of 1g substance by 1°C.Specific heat of water = 1 cal/g °CFormula : Q = mcΔT☃ Let's calculate :D➢ Q = mcΔT
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..Specific heat of substance is defined as the heat required to increase temperature of 1g substance by 1°C.Specific heat of water = 1 cal/g °CFormula : Q = mcΔT☃ Let's calculate :D➢ Q = mcΔT➢ Q = 10 × 1 × (40 - 30)
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..Specific heat of substance is defined as the heat required to increase temperature of 1g substance by 1°C.Specific heat of water = 1 cal/g °CFormula : Q = mcΔT☃ Let's calculate :D➢ Q = mcΔT➢ Q = 10 × 1 × (40 - 30)➢ Q = 10 × 10
Mass of water = 10gInitial temperature = 30°CFinal temperature = 40°CWe have to find heat required to raise temperature of water..Specific heat of substance is defined as the heat required to increase temperature of 1g substance by 1°C.Specific heat of water = 1 cal/g °CFormula : Q = mcΔT☃ Let's calculate :D➢ Q = mcΔT➢ Q = 10 × 1 × (40 - 30)➢ Q = 10 × 10➢ Q = 100 cal
Answer :
Mass of water = 10g
Initial temperature = 30°C
Final temperature = 40°C
We have to find heat required to increase temperature
Specific heat capacity of substance is defined as the heat required to increase temperature of 1g substance by 1°C.
- Q = m × c × ΔT
SHC of water = 1 cal/g °C
⇒ Q = m × c × ΔT
⇒ Q = 10 × 1 × (40-30)
⇒ Q = 10 × 10
⇒ Q = 100 cal :D