Question

Calculate required heat energy (Q)to change 10g of water from 30 celsius to 40 celsius

Answer 1

Answer:

$\boxed{\sf Heat \ energy \ required \ (Q) = 0.1 \ kcal}$

Given:

Mass of water (m) = 10 g

Initial temperature ($\sf T_1$ )= 30°C

Final temperature ($\sf T_2$) = 40°C

To Find:

Heat energy required (Q) to change 10g of water from 30°C to 40°C

Explanation:

As we know,

Specific heat capacity of water (C) = 1 cal/g°C

Formula:

$\boxed {\bold{ \sf Q = mC \Delta T}}$

$\boxed{ \bold{ \sf Q = mC(T_2 - T_1)}}$

Substituting values of m, C, $\sf T_1$ & ($\sf T_2$ in the equation:

$\sf \implies Q = 10 \times 1 \times (40 - 30)$

$\sf \implies Q = 10 \times 10$

$\sf \implies Q = 100 \: cal$

$\sf \implies Q = 0.1 \: kcal$

$\therefore$

Heat energy required (Q) to change 10g of water from 30°C to 40°C = 0.1 kcal

Answer 2

Answer:

Q = mC∆T

Q = 10 × 1 × 10

Q = 100 cal