Question

calculate required heat energy to change 12 gram of ice at -10 degree water at 0° C​

Answer 1

Answer:

The given,

mass of ice( m)=12gm

=12/1000

=0.0012 kg

specific heat capacity of ice(s)=2100j/kg c

chanage in temperature(dt)=10

Heat required (Q)=msdt

=0.0012*2100*10

=25.2j(ans)

Explanation:

I hope this solution is helpful for you.

Answer 2

Answer:

mass of ice=12gms

=12/1000

=0.0012kg

specific heat capacity of ice=2100j/kg

change in temperature=10

heat required=msdt

= 0.0012 ×2100×10

=25.2j