Calculate required heat energy to change 12g of ice at -10° C into water vapour at 100°C.
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hi mate, here is your answer
Explanation:
To convert 12 gram -10 degree Celsius is 0 degree Celsius 12 gram water the required heat is 80×12+800=960 +800=1760 cal..
To convert 12 gram 0 degree celsius to 100 degree Celsius the required heat is 12×537 =6444...cal
the total heat is (1760+6444)=8204 cal..please mark my brain list..
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