Calculate required heat energy to change 12g of ice at 10c into watervapour at 100c
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Answered by
18
Answer:
Explanation:
To convert 12 gram -10 degree Celsius is 0 degree Celsius 12 gram water the required heat is 80×12+800=960 +800=1760 cal..
To convert 12 gram 0 degree celsius to 100 degree Celsius the required heat is 12×537 =6444...cal
the total heat is (1760+6444)=8204 cal ..please mark my brain list.
Answered by
3
Answer:
To convert 12 gram -10 degree Celsius is 0 degree Celsius 12 gram water the required heat is 80×12+800=960 +800=1760 cal.. the total heat is (1760+6444)=8204 cal ..
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