Question

calculate resistance of A and B​

Answer 1

Answer:

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Explanation:

Resistors of 3Ω and 2Ω are also in series.

∴ Their equivalent resistance, R1 =3Ω+2Ω

Resistors of 6Ω and 4Ω are also in series.

∴ Their equivalent resistance, R2 =6Ω+4Ω

Now, R2, 30Ω and R2 are in parallel.

Let R be the equivalent resistance.

Then,

$= \frac{1}{R} = \frac{1}{R1} + \frac{1}{30} + \frac{1}{R2}$

$= \frac{1}{5} + \frac{1}{30} + \frac{1}{10}$

$= \frac{6 + 1 + 3}{30} = \frac{10}{30}$

or

$R = \frac{30}{10} = 3Ω$

Hence, the equivalent resistance between A and B is 3Ω

Answer 2

$\huge\tt\red{❥}\tt\pink{A}\tt\blue{N}\tt\green{S}\tt\purple{W}\tt\orange{E}\tt\orange{R}\huge\tt\purple{᭄}$

$\color{Salmon}{=>Solution}$

Given:-

6

7

9

8

To Find:-

The Calculation

Solution:-

Resistors of 31 and 20 are also in series.

.. Their equivalent resistance, R1 =30+20

Resistors of 60 and 40 are also in series.

.. Their equivalent resistance, R2 =60+402

Now, R2, 300 and R2 are in parallel.

Let R be the equivalent resistance.

Then,

R=30/10 => 3

Hence, the equivalent resistance between A and B is 3

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