calculAte resistances
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We can say that the three 7ohm resistors are parallel with each other.
Let P be the equivalent resistances of the three resistors.
So, (1/P) = (3/7)
P = 7/3 ohm.
Then, P and a 7 ohm resistor near the point B is in series.
Let Q be that equivalent resistance.
Q = (7/3) + 7 = 28/3 ohm
The remaining 7 ohm resistor and Q are in parallel.
Hence, The final resistance(say, R) be,
(1/R) = (3/28) + (1/7) = 49/196
R = 196/49 ohm.
Using Ohm's Law,
Voltage = Current × Resistance
= 1 × 196/49
Voltage = 196/49 V
Power = Voltage × Current
= (196/49) × 1
Power = 196/49 W.
-WonderGirl
Let P be the equivalent resistances of the three resistors.
So, (1/P) = (3/7)
P = 7/3 ohm.
Then, P and a 7 ohm resistor near the point B is in series.
Let Q be that equivalent resistance.
Q = (7/3) + 7 = 28/3 ohm
The remaining 7 ohm resistor and Q are in parallel.
Hence, The final resistance(say, R) be,
(1/R) = (3/28) + (1/7) = 49/196
R = 196/49 ohm.
Using Ohm's Law,
Voltage = Current × Resistance
= 1 × 196/49
Voltage = 196/49 V
Power = Voltage × Current
= (196/49) × 1
Power = 196/49 W.
-WonderGirl
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