Physics, asked by saam3001, 1 year ago

Calculate rhe mass of hydrogen liberated when 230 grams of sodium reacts with excess of water at STP

Answers

Answered by kvnmurty
20
Atomic or molecular mass of Na = 23
230 gms = 10 moles

2 Na + 2 H2O ==> H2 (g)+ 2 Na OH

2 moles of Sodium give 2 grams or 1 mole of H2. So 10 moles give grams.

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Answered by abhi178
37
 see the reaction,
    2Na + 2H
→ 2NaOH + H
you can see that
        2mole of Na form 1 mole hydrogen gas 
        46g of Na form 2g hydrogen gas 
        230g of Na form 2*230/46 g hydrogen gas hence
the amount of 
H₂ =  10 g

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