Question

calculate rms speed of N2 gas in m/s at a temp of 280 K ?

Answer 1

We have R.M.S

μ =  in this M = Molar mass

And in the case of Nitrogen gas, T = 27 + 273 = 300 K.R = 8.314 (kg  /  )/ K mol

Since molar mass of Nitrogen gas = 28 gm/mol = 2.8 x  kg/mol

Hence μ =  = [ 3 x 8.314 x 300 / 2.8 x  ] = [267235.7 = 516.9m/s

So the r.m speed for oxygen gas at 0°C (273K) = 516.9 m/s